Answer:
it's easy u just have to put them in a calculator the way they are it will give you your answer atleast I think so hope this helps
The answer is B. Heat flows from the hand to the ice cream. The state of equilibrium won't occur for this since the only reactant is heat.
The pH of the solution is 2.54.
Explanation:
pH is the measure of acidity of the solution and Ka is the dissociation constant. Dissociation constant is the measure of concentration of hydrogen ion donated to the solution.
The solution of C₆H₂O₆ will get dissociated as C₆HO₆ and H+ ions. So the molar concentration of 0.1 M is present at the initial stage. Lets consider that the concentration of hydrogen ion released as x and the same amount of the base ion will also be released.
So the dissociation constant Kₐ can be written as the ratio of concentration of products to the concentration of reactants. As the concentration of reactants is given as 0.1 M and the concentration of products is considered as x for both hydrogen and base ion. Then the
![K_{a}=\frac{[H^{+}][HB] }{[reactant]}](https://tex.z-dn.net/?f=K_%7Ba%7D%3D%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5BHB%5D%20%7D%7B%5Breactant%5D%7D)
[HB] is the concentration of base.
![8 * 10^{-5} =\frac{x^{2} }{0.1}\\\\\\x^{2} = 8 * 10^{-5}*0.1](https://tex.z-dn.net/?f=8%20%2A%2010%5E%7B-5%7D%20%3D%5Cfrac%7Bx%5E%7B2%7D%20%20%7D%7B0.1%7D%5C%5C%5C%5C%5C%5Cx%5E%7B2%7D%20%3D%208%20%2A%2010%5E%7B-5%7D%2A0.1)
![x^{2} = 0.08 * 10^{-4}\\ \\x = 0.283*10^{-2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%3D%200.08%20%2A%2010%5E%7B-4%7D%5C%5C%20%5C%5Cx%20%3D%200.283%2A10%5E%7B-2%7D)
Then
![pH = - log [x] = - log [ 0.283 * 10^{-2}]\\ \\pH = 2 + 0.548 = 2.54](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5Bx%5D%20%3D%20-%20log%20%5B%200.283%20%2A%2010%5E%7B-2%7D%5D%5C%5C%20%5C%5CpH%20%3D%202%20%2B%200.548%20%3D%202.54)
So the pH of the solution is 2.54.
Answer:
where are the following??
like anything? any animal?
Explanation:
Mass of aspirin = 0.025 g
Molar mass of C9H8O4 is 180.1583 g/mol
moles of aspirin = .025g / 180.1583 g/mol = 0.000138767 moles
volume solution = .250 L
molarity of the solution = 0.000138767 moles / .250L =5.551 x 10 ^-04 Moles / liter
for aspirin i = Vant'Hoff factor = 1 particle in solution
T = 25 + 273 =298 K
osmotic pressure = M x R x T x i =
5.551 x 10 ^-04 mole L -1 x 0.08206 L atm K−1 mol−1 x 298 K x 1 = 0.0136 atmospheres