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KiRa [710]
3 years ago
14

Water is placed outside at 298 K overnight. Which statement best describes what would happen?a)298 K converts to -24.9 °C, so th

e water would freezeb)298 K converts to 24.9 °C, so the water would remain in its liquid statec)298 K converts to 24.9 °C, so the water would freeze
Chemistry
1 answer:
user100 [1]3 years ago
7 0

Answer: b)298 K converts to 24.9 °C, so the water would remain in its liquid state

Explanation: Kelvin is an absolute temperature scale, that means that 0K (zero Kelvin) is the lowest temperature possible and compare to Celsius scale the change of 1 degree is the same, but 0°C is the same as 273,1K

So, in order to convert Kelvin to Celsius you have to subtract 273,1

In this case, 298K - 273,1 = 24,9°C

This temperature is room temperature, so water is in liquid state.

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What is the ph of a 0.10 m solution of ethylamine at 25 oc? the pkb of ethylamine at 25 ºc is 3.25. ethylamine is a weak base?
denis-greek [22]
To determine the pH of a weak base, we use the equation:

pH = 14 + 0.5 log Kb

Therefore, 


pH = 14 + 0.5 log 3.25
pH = 14.26

A weak base is a base which does not fully dissociates into ions when in solution. The solution would contain cations, anions and the compound itself. Hope this helps.
5 0
3 years ago
1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)
Mrac [35]

Answer:

Mass = 245.72 g

Explanation:

Given data:

Mass of SrCl₂ react = ?

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Solution:

SrCl₂  +  2H₂SO₄     →     2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles =  300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and  H₂SO₄.

                   H₂SO₄         :       SrCl₂

                        2             :           1

                      3.1             :         1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

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Question 3 of 10
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Explanation:

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I need help with two questions.
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Answer:

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1 and 5 are definitely significant. The zeros might not be significant .
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