Answer:
10.08 L.
Explanation:
- If we assume that CO₂ gas behaves ideally at STP (standard T(0.0 °C) and P(1.0 atm)):
<em>It is known that 1.0 mole of ideal gas occupies 22.4 L at STP conditions.</em>
<em></em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CO₂ gas occupies → 22.4 L.
0.45 mole of CO₂ gas occupies → ??? L.
<em>∴ The volume occupied by 0.45 mole of CO₂ gas </em>= (0.45 mol)(22.4 L)/(1.0 mol) = <em>10.08 L.</em>
Answer:
The half life time of first order reaction is 1.3 sec
Explanation:
Given:
First order rate constant

Initial concentration
M
From the formula of first order half life time,

So half life time is given by,

sec
Therefore, the half life time of first order reaction is 1.3 sec.
RMM of CaH2=20+(1x2)=22
Number of moles or formula units
=mass/RMM
=8.294/22
=0.377