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KiRa [710]
3 years ago
14

Water is placed outside at 298 K overnight. Which statement best describes what would happen?a)298 K converts to -24.9 °C, so th

e water would freezeb)298 K converts to 24.9 °C, so the water would remain in its liquid statec)298 K converts to 24.9 °C, so the water would freeze
Chemistry
1 answer:
user100 [1]3 years ago
7 0

Answer: b)298 K converts to 24.9 °C, so the water would remain in its liquid state

Explanation: Kelvin is an absolute temperature scale, that means that 0K (zero Kelvin) is the lowest temperature possible and compare to Celsius scale the change of 1 degree is the same, but 0°C is the same as 273,1K

So, in order to convert Kelvin to Celsius you have to subtract 273,1

In this case, 298K - 273,1 = 24,9°C

This temperature is room temperature, so water is in liquid state.

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How much volume would 0.450 mol CO2 gas occupy?
umka21 [38]

Answer:

10.08 L.

Explanation:

  • If we assume that CO₂ gas behaves ideally at STP (standard T(0.0 °C) and P(1.0 atm)):

<em>It is known that 1.0 mole of ideal gas occupies 22.4 L at STP conditions.</em>

<em></em>

<u><em>Using cross multiplication:</em></u>

1.0 mole of CO₂ gas occupies → 22.4 L.

0.45 mole of CO₂ gas occupies → ??? L.

<em>∴ The volume occupied by 0.45 mole of CO₂ gas </em>= (0.45 mol)(22.4 L)/(1.0 mol) = <em>10.08 L.</em>

5 0
3 years ago
The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is
Diano4ka-milaya [45]

Answer:

The half life time of first order reaction is 1.3 sec

Explanation:

Given:

First order rate constant K = 0.54 M^{-1} s^{-1}

Initial concentration = 0.54 M

From the formula of first order half life time,

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So half life time is given by,

{t_{\frac{1}{y2} } } = \frac{0.693}{0.54}

{t_{\frac{1}{y2} } }  = 1.3 sec

Therefore, the half life time of first order reaction is 1.3 sec.

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How many CaH2 formula units are present in 8.294 g of CaH2?
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RMM of CaH2=20+(1x2)=22
Number of moles or formula units
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=8.294/22
=0.377
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andre [41]
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