Question

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

Answer 1

Answer:

Amount of $H_{2}O$ produced will be half of its original value.

Explanation:

Balanced reaction: $HCl+NaOH\rightarrow NaCl+H_{2}O$

According to balanced equation, 1 mol of HCl reacts with 1 mol of NaOH to produce 1 mol of $H_{2}O$

If amount of reactants (NaOH and HCl) are halved then we can write-

0.5 mol of HCl reacts with 0.5 mol of NaOH to produce 0.5 mol of $H_{2}O$.

So, it is evident that amount of $H_{2}O$ to be produced will be half if amount of reactants are halved.