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laila [671]
2 years ago
13

Write two half‑reactions to describe each of these metal displacement reactions. Include phase symbols.

Chemistry
1 answer:
spin [16.1K]2 years ago
7 0

Mg (s) ---> Mg²⁺ (aq) + 2e

Co²⁺ (aq)  + 2e ---> Co(s)

Cu (s) ---> Cu²⁺ (aq) + 2e

Au²⁺ (aq)  + 2e ---> Au(s)

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How many atoms are in 17 moles of O?
omeli [17]

Answer:

67

Explanation:

5 0
3 years ago
When researchers cool a gas, which of the following has occurred? Select all that apply.
Ne4ueva [31]

Answer is: Velocity and spacing of particles is reduced and Volume of substance decreases relative to temperature decrease.

Charles' Law (The Temperature-Volume Law) - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:

V₁/T₁ = V₂/T₂.

When temperature goes down, the volume also goes down.

Velocity is equivalent to a specification of its speed and direction of motion, it is a physical vector quantity. Less enegry (lower temperature), lower the velocity.

5 0
3 years ago
Read 2 more answers
P-fluoroanisole reacts with sulfur trioxide and sulfuric acid. Draw the major product of this substitution reaction; if applicab
Ipatiy [6.2K]

Answer: (Structure attached).

Explanation:

This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.

The aromatic ring in p-fluoroanisole has two sustituents, an <u>halogen</u> and a <u>methoxy group</u>, which are <em>ortho-para</em> directing substituents.

Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using <u>sulfur trioxide as an electrophile</u> (very reactive).

The reaction occurs in three steps:

  1. The attack on the electrophile forms the sigma complex.
  2. The loss of a proton regenerates an aromatic ring.
  3. The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).

Normally, a mixture of <em>ortho-para</em> substituted products would be obtained. However, since both <em>para</em> positions are occupied, only the <em>ortho </em>substituted product is obtained here.

8 0
3 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
Write any three acids which are used in our daily life. Also, write an application of each​
lidiya [134]
Sodium fluoride- to brush teeth
Citric acid- orange juice for breakfast
Sodium hydroxide- cleaning agent
3 0
2 years ago
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