Find the product. (-2 x^2 )^ 3 ·3 x

Mathematics

1 answer:

Lemur [1.5K]3 years ago

6 0

Answer:

-24x^7

Step-by-step explanation:

Note that (-2)^3 = -8, and so:

(-2 x^2 )^ 3 ·3 x = -8*x^6 * 3*x, or -24x^7

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The sum of two integers is (-32). Their quotient is 7. What are the integers?

Aneli [31]

<h3>Answer: -28 and -4</h3>

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Explanation:

Let x and y be the two integers such that |x| > |y|. This is another way of saying that x is further away from 0 compared to y.

Their quotient being 7 means x/y = 7 which rearranges to x = 7y

The sum of the integers is -32 which allows us to say....

x+y = -32

7y+y = -32

8y = -32

y = -32/8

y = -4

Use this y value to find x

x = 7y

x = 7*(-4)

x = -28

The two integers are -28 and -4.

8 0

3 years ago

Hey can you please help me posted picture of question

Leni [432]

Answer:
(x+4)(x+5) = 0

Explanation:
The standard form of the quadratic equation is:
ax² + bx + c = 0

The given equation is:
x² + 20 = -9x
Adding 9x to both sides would make us reach the standard form which would be:
x² + 9x + 20 = 0
By comparison:
a = 1
b = 9
c = 20

To factor the equation, we would need to use the quadratic formula shown in the attached image.

By substitution, we ould find that:
either x = $\frac{-9+ \sqrt{(9)^2-4(1)(20)} }{2(1)} = -4$

This means that the first factor is (x+4)

or x = $\frac{-9+ \sqrt{(9)^2-4(1)(20)} }{2(1)} = -5$

This means that the second factor is (x+5)

Based on the above, the factored form of the equation would be:
(x+4)(x+5) = 0

Hope this helps :)