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3 years ago

14

Time Limit!

1 answer:

DENIUS [597]3 years ago

7 0

The correct answer is B.3,072. The method is quite simple all you need to do is add the previous number to itself in order to get the next term e.g 3+3=6.............24+24= 48 until the eleventh term.

Hope this helps ya

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Find the least common denominator (LCD) for these fractions.

irinina [24]

16. LCD: 48 because 1/4= 12/48, 1/12=4/48, 11/16= 33/48 and they all share 48 as the denominator

17. LCD: 168 because 5/56= 15/168, 7/24= 49/168, 7/12= 98/168, 5/42= 20/168

18. LCD: 30 because 2/1= 60/30, 1/5= 6/30, 1/10= 3/30, 5/6= 25/30

5 0

3 years ago

Write two different expressions that are equal to 12-16x use factoring if possible

guajiro [1.7K]

1) 2(6-8x)

2) 4(3-4x)

That seems about right.

7 0

3 years ago

Read 2 more answers

What does x equal is -12=2x^2+5x

geniusboy [140]

The answer is no real solutions

7 0

3 years ago

Use the distance formula to determine the distance between (-8,10) and (-6,7)

hjlf

Answer:

Distance: $\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where:

$d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$
$(x_1,y_1)$ are the coordinates of the first point
$(x_2,y_2)$ are the coordinates of the second point

We are given that:

$(x_1,y_1)=(-8,10)$
$(x_2,y_2)=(-6,7)$

To determine the value of our distance, $d$ , we plug in our given information into the formula and solve for

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-6-(-8))^2+(7-10)^2}$

$d=\sqrt{(-6+8)^2+(-3)^2}$

$d=\sqrt{(2)^2+(-3)^2}$

$d=\sqrt{4+9}$

$d=\sqrt{13}$

Therefore, the distance between $(-8,10)$ and $(-6,7)$ is $\sqrt{13}$ units.

See the attached graph for a visual.

5 0

3 years ago

In the last race , the first car in the pit used 1 3/4 tanks of gas, the second car used 2 1/8 and the third car used 1 1/2 tank

riadik2000 [5.3K]

Answer: $-5\frac{3}{8}$ tanks of gas

Step-by-step explanation:

Let the x be the number of tanks of gas, then

The amount of gas used by first car= $1\frac{3}{4}x=\frac{7}{4}x$

The amount of gas used by second car= $2\frac{1}{8}x=\frac{17}{8}x$

The amount of gas used by third car= $1\frac{1}{2}x=\frac{3}{2}x$

Thus, the total change in the amount of gas for all three cars= $\frac{7}{4}x+\frac{17}{8}x+\frac{3}{2}x$

$=x(\frac{7}{4}+\frac{17}{8}+\frac{3}{2})\\\\=x(\frac{14+17+12}{8})\\\\=x(\frac{43}{8})\\=5\frac{3}{8}x$

Since, the amount of gas $5\frac{3}{8}$ tanks of gas is used for all three cars.

Therefore, the total amount would be negative .

hence, the answer is $-5\frac{3}{8}$ tanks of gas.

8 0

3 years ago