Answer: 34 cm
Step-by-step explanation:
Hi, since the situation forms 2 right triangles (see attachment) we have to apply the Pythagorean Theorem (to one triangle)
c^2 = a^2 + b^2
Where c is the hypotenuse of the triangle (in this case the distance between corners) and a and b are the other sides.
Replacing with the values given:
c^2 = 12^2 + 12^2
c^2 =144+144
c^2 = 288
c = √288
c = 16.97 cm = 17 cm (rounded)
The other diagonal has the exact same lenght (because the flag is a square)
So, we have to multiply the length of the ribbon by 2:
17 x2 = 34 cm
Feel free to ask for more if needed or if you did not understand something.
Answer:
p=6
Step-by-step explanation:
4p+12=36
(subtract 12)
4p=24
(divide by 4)
p=6
Answer:
Cards C and E
Step-by-step explanation:
Remember that irrational numbers cannot be written as a fraction of two integers:
Is 10 irrational? No, because 10 can be written as a fraction (ex. 10/1, 20/2, etc.)
Is 6/5 irrational? No, because it is a fraction.
Is π irrational? Yes, because it can't be written as a fraction as its digits continue infinitely without repetition.
Is 11/4 irrational? No, because it is a fraction.
Is 8.25635... irrational? Yes, because the ellipsis shows the digits continue infinitely without repetition, otherwise there would be a bar over the digits to show repetition
Is -7 irrational? No, because it can be written as a fraction (ex. -7/1, -14/2, etc.)
Is 6.31(bar) irrational? No, because the bar shows that the digits 3 and 1 repeat.
Therefore, only cards C and E are irrational.
Answer:
The answer is A
Step-by-step explanation:
Answer: 228 students
Step-by-step explanation:
Since the results for the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = test reults
µ = mean score
σ = standard deviation
From the information given,
µ = 1700 points
σ = 75 points
We want to find the probability of students expected to score above 1850 points. It is expressed as
P(x > 1850) = 1 - P(x ≤ 1850)
For x = 1850,
z = (1850 - 1700)/75 = 150/75 = 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.97725
P(x > 1850) = 1 - 0.97725 = 0.02275
If 10,000 students take the exam, then the number of students you would expect to score above 1850 points is
0.02275 × 10000 = 228 students
