Answer:
<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>
Step-by-step explanation:
Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units
From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.
By the definition of rhombus, diagonals meet at right angles.
Implies that PQ = QA
x+2 = 3x - 14
x-3x=-14-2
-2x=-16
2x = 16
dividing by 2 on both sides, we will get,
<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>
The line segment 
( since x=8)
<h3>∴
units</h3>
Tan(angle) = opposite/adjacent
tan(x) = 90/51
x = arctan(90/51)
x = 60.461217740442
which rounds to 60 when rounding to the nearest whole number
Answer: 60
Answer:
the answer is C 6x2 .....................
Answer:
(3,-4)
Step-by-step explanation:
rise=go up
run=go left or right
if you go left its negitive if you right its positive
always start with the lower dot
hopes this helps id you need more help just message me
The volume of the pyramid is 448m^3
(16)(12)(7)/3
= 1334/3
= 448
