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Georgia [21]
3 years ago
9

Zoe and Hannah share tips in the ratio 3:7. Last week, Zoe received £24. How much did Hannah receive last week?​

Mathematics
2 answers:
valina [46]3 years ago
5 0

Answer:

Hannah received £56 last week

Step-by-step explanation:

Zoe as a ratio of 3 of the tips that was shared with Hannah. if Zoe received £24 for are share of ratio 3, therefore, 1 share ratio is £24/3 = £8.

Since Hannah has 7 share ratio of the tip, and 1 share ratio is £8, therefore, Hannah will receive £8*7 = £56

Therefore Zoe and Hannah share the total ratio of the tips which is 3+7 = 10.

And the total tips shared is £8*10 = £80

frozen [14]3 years ago
4 0

Answer:

56

Step-by-step explanation:

If the ratio of Zoe; Hannah is 3:7 and Zoe got 24 than we have to divide the 24 by 3 so we can multiply it by 7. This is because since the Zoe is the 3 and it isn't a 1 it isn't the starting point for either of the ratios we cannot multiply the 24 by 7.

24 ÷ 3 = 8

Now we multiply the 8 by 7 so that we know have many tips Hannah made

8 × 7 = 56

Hannah made 56 in tips

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197%

Step-by-step explanation:

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3 years ago
It’s asking for LATERAL surface area btw
lozanna [386]

Answer:

Lateral surface area = 826.5 m²

Step-by-step explanation:

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Lateral surface area of the triangular prism = Perimeter of the triangular base × Height

Perimeter of the triangular base = 6 + 11 + 12

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5 0
3 years ago
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

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Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

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The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

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3 years ago
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