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Tasya [4]
3 years ago
7

A family of 2 adults and 3 children goes to a play Admission cost $8 per adult and $5 per child.What expression would show the t

otal admission cost for the family
Mathematics
2 answers:
alexdok [17]3 years ago
7 0
[2x8]+[3x5]=31 that's the answer
Anarel [89]3 years ago
3 0
(8x2)+(3x5) is the expression
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Monica [59]
3 and 3 or 1 and 9 not really sure of anything else
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Maura runs 5 miles in 1.25 hours. Ava runs 3 miles in 50 minutes or 0.83¯ hour.<br> Who runs faster?
kenny6666 [7]

Answer:

║⊕║∵°·∵∴Hello :)∴∵·°∵∴║⊕║

Your answer should be:

Maura runs faster.

Step-by-step explanation:

I hope this helped!

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8 0
2 years ago
I need help on these 3 problems cause I’m stuck on them someone pls help
Pavlova-9 [17]

Answer:

Step-by-step explanation:

4. Nicole can make 7 quarts of lemonade with 10 cups of sugar.

If 3/4 cup of sugar is used to make 1 quart of lemonade and 10 cups of sugar are available, then you multiply 3 times 10 (when multiplying fractions, you only multiply with the numerator, not the denominator) which will give you 30.

Now, you can write it as 30/4. Using simple division, you find that 30/4 is 7.5 (or 7 and 1/2), and because we're trying to find how many full quarts we can make using 10 cups of sugar, your answer will be 7.

5. Each person will get 0.83 repeating (or 5/6) boxes of raisins.

In this problem, we have 6 people and we have to share 5 boxes of raisins among all of them. We know that each person can't get 1 because there would have to be 6 boxes (1 for each person), so we have a fraction (or decimal, depending on where you're at).

Dividing 5/6, you'll simply get 5/6 because you can't simply this any further, but if you were to write this as a fraction, you'd get 0.83 repeating (over the 3).

6. Each class will receive 30 boxes of cracker jacks.

We know that there are 153 boxes of cracker jacks available, and this needs to then be split among 5 different classes. So, to find the answer, we have to divide 153 by 5. In doing that, we get 30.6, but because we're trying to find the whole number that the classes will receive, as you can't get a fraction of a box (at least, I assume), then each class will get 30 with 3 boxes remaining.

3 0
2 years ago
Which two expressions are equivalent?
Mnenie [13.5K]

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4 0
2 years ago
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Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of d^2y/dx
nikdorinn [45]

Answer:

Differentiation will give you the gradient for the tangent at any point, and you use the product rule whenever a function can be thought of as two functions multiplied together.

If

f

(

x

)

=

g

(

x

)

×

h

(

x

)

then

f

'

(

x

)

=

g

'

(

x

)

h

(

x

)

+

g

(

x

)

h

'

(

x

)

so if

y

=

x

×

sin

x

then

d

y

d

x

=

1

×

sin

x

+

x

×

cos

x

=

sin

x

+

x

cos

x

We know that

x

=

π

2

, so the gradient is

m

=

sin

(

π

2

)

+

π

2

cos

(

π

2

)

=

1

+

π

2

×

0

=

1

Therefore, we can say that

y

=

m

x

+

c

y

=

(

1

)

x

+

c

y

=

x

+

c

So all we really need to find now is the value for

c

, the

y

intercept. We do this by working out a point

(

x

,

y

)

on the graph. We are already given that

x

=

π

2

, so

y

=

x

sin

x

=

π

2

sin

(

π

2

)

=

π

2

×

1

=

π

2

∴

(

x

,

y

)

=

(

π

2

,

π

2

)

Now we substitute this into the equation we already have for the tangent,

y

=

x

+

c

,

(

x

,

y

)

=

(

π

2

,

π

2

)

π

2

=

π

2

+

c

c

=

π

2

−

π

2

=

0

∴

y

=

x

+

c

=

x

+

(

0

)

=

x

which means the tangent to the curve

y

=

x

sin

x

at

(

π

2

,

π

2

)

is simply

y

=

x

.

3 0
2 years ago
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