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3 years ago

7

A family of 2 adults and 3 children goes to a play Admission cost $8 per adult and $5 per child.What expression would show the t

otal admission cost for the family

2 answers:

alexdok [17]3 years ago

7 0

[2x8]+[3x5]=31 that's the answer

Anarel [89]3 years ago

3 0

(8x2)+(3x5) is the expression

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Find two consecutive even integers such that twice the second is the same as 186 less than the first integer.

Alisiya [41]

Step-by-step explanation:

let the 2 integers be x and x + 1

2(x + 1) + 186 = x

2x + 188 = x

x = -188

therefore the 2 integers are -188 and -187

Topic: Algebraic equations

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

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3 years ago

Check the box labeled Show Altitude of Triangle ABC. The altitude divides into and through the point you determined in question

maw [93]

Answer:

Step-by-step explanation:

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3 years ago

(please help will mark brainlist)

otez555 [7]

Answer:

9a^3b^3.

Step-by-step explanation:

The GCF of 9 and 27 is 9.

For a^4 and a^3 it is a^3.

For b^4 and b^3 it is b^3.

Answer is therefore:

9a^3b^3.

3 0

2 years ago

Read 2 more answers

14 less than 8 times 8 number is 3 more than four times the number what is the answer

aliina [53]

Answer:The answer is 11.75

Step-by-step explanation:

5 0

3 years ago

A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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2 years ago