Question

Someone please help me with this

Answer 1

Answer:

3/2 and -2

Step-by-step explanation:

The quadratic formula is $x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$. Here a=2, b=1, and c=-6.

Substitute and you'll have:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-1+/-\sqrt{1^2-4(2)(-6)} }{2(2)}=\frac{-1+/-\sqrt{1+48} }{4)}$

$\frac{-1+/-\sqrt{1+48} }{4}=\frac{-1+/-\sqrt{49} }{4}=\frac{-1+/-7 }{4}= \frac{3}{2} , -2$