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2 years ago

9

A sample of a substance has a high density, yet a low particle motion. This sample must be a

2 answers:

kiruha [24]2 years ago

5 0

Answer:

A solid

With solids the particles are very close together making the substance very dense, and because the particles are so close they don't have very much room to move, making the particle motion very low.

vitfil [10]2 years ago

4 0

It must be a high destiny

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Compute the number of grams(g) of lead in 22.5 moles of lead.

iogann1982 [59]

Answer:

4662 in grams

Explanation:

hope this helps :).

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2 years ago

When electrons move closer to a more electronegative atom, what happens? the more electronegative atom is _____?

larisa86 [58]

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3 years ago

2. Calculate the mass of 3.47x1023 gold atoms.

lapo4ka [179]

3.47 x $10^{23}$ atoms of gold have mass of 113.44 grams.

Explanation:

Data given:

number of atoms of gold = 3.47 x $10^{23}$

mass of the gold in given number of atoms = ?

atomic mass of gold =196.96 grams/mole

Avagadro's number = 6.022 X $10^{23}$

from the relation,

1 mole of element contains 6.022 x $10^{23}$ atoms.

so no of moles of gold given = $\frac{3.47 X 10^{23} }{6.022 X 10^{23} }$

0.57 moles of gold.

from the relation:

number of moles = $\frac{mass}{atomic mass of 1 mole}$

rearranging the equation,

mass = number of moles x atomic mass

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3 years ago

(6 points) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m

Cloud [144]

<u>Answer:</u> The equation to calculate the mass of remaining isotope is $[A]=\frac{20}{10^{-0.217t}}$

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = $\ln 4=1.386yrs$

Putting values in above equation, we get:

$k=\frac{0.693}{1.386yrs}=0.5yrs^{-1}$

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$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.5yr^{-1}$

t = time taken for decay process

$[A_o]$ = initial amount of the sample = 20 grams

[A] = amount left after decay process = ? grams

Putting values in above equation, we get:

$0.5=\frac{2.303}{t}\log\frac{20}{[A]}$

$[A]=\frac{20}{10^{-0.217t}}$

Hence, the equation to calculate the mass of remaining isotope is $[A]=\frac{20}{10^{-0.217t}}$

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3 years ago

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