What is the definition of pendulum

Chemistry

2 answers:

Mama L [17]2 years ago

5 0

Answer:

weight hung from a fixed point so that it can swing freely backward and forward.

TiliK225 [7]2 years ago

3 0

Answer:

a weight hung from a fixed point so that it can swing freely backward and forward, especially a rod with a weight at the end that regulates the mechanism of a clock.

Explanation:

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H2(g)+p4(s)ph3(g) what the answer ?

disa [49]

Answer:

6H2 + P4→ 4PH3

Explanation:

Phosphorus has 4 in it and hydrogen has 3 in it. in order to balance it, we have to put 4 in front of phosphine so that the phosphorus on the product side has an equal amount as to the one on the reactant side.

the only one left to balance is hydrogen and so in order to balance it we put a 6 on h2 because the hydrogen in the product size becomes 12 (4 * 3).

therefore the hydrogen on the reactant side becomes 12 as well (6 * 2)

8 0

2 years ago

Draw the expanded structural formula for the condensed formula (CH3)2CHCH2OCH2CH3 . Draw all hydrogen atoms

prisoha [69]

We have that the Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below

From the Question

(CH3)2CHCH2OCH2CH3

Generally for the condensed formula (CH3)2CHCH2OCH2CH3

We consider that this is a single bond connecting them

We consider

Hydrogen H(1)

Oxygen(8)

Carbon(6)

In conclusion

The Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below.

For more information on this visit

brainly.com/question/24102840

5 0

2 years ago

Draw the structural formula of the major product of the reaction of (S)-2,2,3-trimethyloxirane with MeOH, H . Use the wedge/hash

Katarina [22]

Answer:

(S)-3-methoxy-3-methylbutan-2-ol

Explanation:

In this case, we have an epoxide opening in acid medium. The first step then is the protonation of the oxygen. Then the epoxide is broken to generate the most stable carbocation. The nucleophile ( $CH_3OH$ ) will attack the carbocation generating a new bond. Finally, the oxygen is deprotonated to obtain an ether functional group and we will obtain the molecule (S)-3-methoxy-3-methylbutan-2-ol.