Answer:
Q = 10.8 KJ
Explanation:
Given data:
Mass of Al= 100g
Initial temperature = 30°C
Final temperature = 150°C
Heat required = ?
Solution:
Specific heat of Al = 0.90 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30°C
ΔT = 120°C
Q = 100g×0.90 J/g.°C× 120°C
Q = 10800 J (10800j×1KJ/1000 j)
Q = 10.8 KJ
Answer:
Bulk matter can exist in three states: gas, liquid, and solid. Gases have the lowest density of the three, are highly compressible, and fill their containers completely
Explanation:
Please mark as brainliest
Answer:
0.29 mol/L
Explanation:
Its density is 1.029 g/ml so in a liter (1000 mL) there is 1029 g of solution, but only 5% is dextrose.
0.05x1029=51.45
So in a liter of D5W solution there is 51.45 g of dextrose.
Dextrose molar mass iss 180.156 g/mol, so in 51.45 g of dextrose there is
51.45/180.156=0.29 mol
In one liter of solution there is 0.29 mol of dextrose, so the molarity of such solution is 0.29 mol/L.
There are no options provided, therefor I cannot answer the question.
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