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navik [9.2K]
2 years ago
13

Consider the chemical equation in equilibrium. A(g) 2B(g) Double headed arrow. C(g) D(g) heat What will happen to the equilibriu

m of this reaction if the temperature is increased? It will shift to the left because heat is released. It will shift to the left because heat is absorbed. It will shift to the right because heat is released. It will shift to the right because heat is absorbed.
Chemistry
1 answer:
Mazyrski [523]2 years ago
6 0

If the temperature is increased then reaction will shift to the left because heat is absorbed.

<h3>What is equilibrium state?</h3>

Equilibrium of any reaction is that state in which concentration of reactant and concentration of product will be constant.

Given chemical reaction is:

A(g) + 2B(g) ⇄ C(g) + D(g)

From the equilibrium state reaction will move only that side which will contribute to maintain the stable state. In the forward reaction heat is released as mention in the question. So, when the temperature of reaction is increased then it shifts towards the left side by absorbing the heat and maintain the stability.

Hence, option (2) is correct, i.e. It will shift to the left because heat is absorbed.

To know more about equilibrium, visit the below link:

brainly.com/question/14297698

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Answer:

\boxed {\boxed {\sf 0.0018 \ mol \ H_2 O }}

Explanation:

First, we need to find the molecular mass of water (H₂O).

H₂O has:

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Use the Periodic Table to find the mass of hydrogen and oxygen. Then, multiply by the number of atoms of the element.

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There are 2 hydrogen atoms, so multiply the mass by 2.

  • 2 Hydrogen: (1.0079 g/mol)(2)= 2.0158 g/mol

Now, find the mass of H₂O. Add the mass of 2 hydrogen atoms and 1 oxygen atom.

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Next, find the amount of moles using the molecular mass we just calculated. Set up a ratio.

0.032 \ g  \ H_2 O* \frac{ 1 \ mol \ H_2 O}{18.0152 \ g \ H_2 O}

Multiply. The grams of H₂O will cancel out.

0.032 * \frac{1 \ mol \ H_2 O}{18.0152 }

\frac{0.032 *1 \ mol \ H_2 O}{18.0152 }

0.00177627781 \ mol \ H_2 O

The original measurement given had two significant figures (3,2). We must round to have 2 significant figures. All the zeroes before the 1 are not significant. So, round to the ten thousandth.

The 7 in the hundred thousandth place tells us to round up.

0.0018 \ mol \ H_2 O

There are about <u>0.0018 moles in 0.032 grams.</u>

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