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Ilya [14]
3 years ago
5

Find the quotient of 85 & .25

Mathematics
1 answer:
KatRina [158]3 years ago
6 0
42.5, just need to multiply
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If f(x)=12x+2(x-1), find f(6)
zavuch27 [327]

Answer:

12x6+2(6-1)

72+2x5

72+10

82

82 is the answer.

Step-by-step explanation:

Just replace the X's in the problem with 6.

5 0
3 years ago
What type of number is Square root of two
DochEvi [55]

Answer:

irrational

The square root of 2 is irrational.

Step-by-step explanation:

5 0
3 years ago
How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi
ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
107=5x+17 simplify your answer as much as possible
olga nikolaevna [1]
107-7=90
90divided 5=18
18*5=90+17=107
I did the work ♥♥♥♥
6 0
2 years ago
Read 2 more answers
O is the centre of the circle, determine the value of v ​
never [62]

Answer:

the angle v =59 degree

..

8 0
3 years ago
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