Knowing that ΔQPT ≅ ΔARZ, a congruent side pair is:
2 answers:
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9514 1404 393
Answer:
40.5 ft
Step-by-step explanation:
Solve for the time at which the balls meet, then find the corresponding height.
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The balls will meet at the height such that the two values of h are the same.
-16t^2 +56t = h = -16t^2 +156t -248
0 = 100t -248
t = 2.48
Using the first equation to find h, we have ...
h = t(-16t +56) = 2.48(-16·2.48 +56) = 40.4736
The balls meet at a height of about 40.5 feet.
