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3 years ago

12

There are 14 people competing and only 4 will win the contest. What percentage does each person have in winning? or what are my

chances in winning?

1 answer:

vova2212 [387]3 years ago

7 0

Answer:

each person would have a 3.5% chance of winning the contest

Step-by-step explanation:

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Please ASAP i need help

NeX [460]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

Alemu, Tulu, Kassa and Tegitu worked for 4 hours, 6 hours, 5 hours

GaryK [48]

As a group they were paid $1000 after putting in 4+6+5+5 = 20 worker-hours.
$1000/(20 worker-hours) = $50/(worker-hour)
Alemu received 4*$50 = $200
Tulu received 6*$50 = $300
Kassa and Tegitu each received 5*$50 = $250

6 0

2 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

Read 2 more answers

Algebraic expression the sum of 12 and k

USPshnik [31]

The answer is 12+k because sum means addition and it says 12 and k therefore you and 12 and k together and the algebraic expression would be 12+k

7 0

3 years ago

Find the different of 52.135 and 31.47

allsm [11]

The difference is 20.665

5 0

3 years ago

Read 2 more answers