Performing laplace transform of the equation.
sY(s) - y(0) + 6Y(s) = 1/(s-4)
(s+6)Y(s) - 2 = 1/(s-4)
Y(s) = 2/(s+6) + 1/(s-4)(s+6), by partial fraction decomposition
Y(s) = 2/(s+6) + 1/10 * (1/(s-4) + 1/(s+6))
Y(s) = 0.1/(s-4) + 2.1/(s+6)
Performing inverse laplace transform,
y(t) = 0.1e^4t + 2.1e^(-6t)
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Based on the information given about the equation, y will be 0.5x + 2.
<h3>How to illustrate the equation?</h3>
From the information given, it should be noted that the equation of the line it represents was given and the y intercept is = (0, 2).
The function to represent y will be:
y = mx + b
y = (1/2)x + 2
y = 0.5x + 2
In conclusion, y = 0.5x + 2.
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As soon as possible after the lecture
The slop is 3 I hope that helped?
