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Nitella [24]
2 years ago
9

Felipe believes that whenever the Moon is in the position that is shown from above (top view) in Diagram A, the Moon always look

s completely bright in the view from Earth, as shown in Diagram B.
Is Felipe correct? If he is correct, explain why the Moon always looks bright from Earth in that position, and explain how he should show light on the Moon in Diagram A. If he is incorrect, explain how else the Moon can look when it is in that position.

Physics
1 answer:
taurus [48]2 years ago
8 0

Answer:he is incorrect

Explanation:he is wrong because if the sunlight is on the opposite side of the earth than the moon, then the sunlight would be blocked by the earth, making the moon dark, because the moon gets its light from the light that is reflected of the surface from the sun

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An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work mu
Maru [420]

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

       = e × V

       = (1.6 × 10⁻¹⁹ C)×(1.2 V)

       = 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

Learn more about work done on a charge here:

<u>brainly.com/question/13946889</u>

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4 0
2 years ago
A race car has a mass of 820 kg. It starts from rest and travels 50.0m in 3.0s. The car is uniformly accelerated during the enti
Contact [7]
A=DELTAv/DELTAt=50/3
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7 0
2 years ago
You're an electrical engineer designing an alternator (the generator that charges a car's battery). Mechanical engineers specify
Julli [10]

Answer:

13.78 mT

Explanation:

The peak voltage ε = ωNAB where ω = angular speed of coil = 1500 rpm = 1500 × 2π/60 rad/s = 50π rad/s = 157.08 rad/s, N = number of turns of coil = 250, A = area of coil = πr² where r = radius of coil = 10 cm = 0.10 m,

A = π(0.1 m)² = 0.03142 m² and B = magnetic field strength

So,

B = ε/ωNA  

substituting the values of the variables into the equation given that ε = 17 V

So, B = ε/ωNA

B = 17 V/(157.08 rad/s × 250 turns × 0.03142 m²)

B = 17 V/(1233.8634 rad-turns-m²/s)

B = 0.01378 T

B = 13.78 mT

8 0
2 years ago
A ball on a frictionless plane is swung around in a circle at constant speed. The acceleration points in the same direction as t
Kitty [74]
I believe it is False, only because the plane is Frictionless. Hope this helps, good luck.
4 0
3 years ago
Read 2 more answers
How do I solve the following problem?
lukranit [14]
Use the impulse-momentum theorem.

Ft = mv

Substitute your known values:

(120kg)(20m/s) = F(1.5)&#10;&#10;F= 1600N

Hope this helps!
7 0
3 years ago
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