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notka56 [123]
3 years ago
11

3. A bee flies forward at 4.9 for 33 s, lands on a flower and stays there for 7s, then flies back along its previous route at 1.

9 for 39 s. What is the average speed of the bee
during the entire time?
O 1.701
O 3.001
O 4.466
O 3.801
None of these is correct.
Physics
1 answer:
igor_vitrenko [27]3 years ago
5 0

Answer:

None of these is correct.

Explanation:

The average speed can be derived from the sum of the total distance traveled and the total time taken.

 Total distance = 4.9 + 1.9  = 6.8

  Total time taken  = 33 + 39  = 72

So;

 Average speed  = \frac{total distance}{total time}  = \frac{6.8}{72}   = 0.014

None of the answer choices given is correct.

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A guitar string is supposed to have a fundamental frequency 256 Hz. It currently has a fundamental frequency 248 Hz when the str
umka2103 [35]

Answer:

The tension to bring the guitar string into tune is 372.95 Hz.

Explanation:

Given;

current frequency, f₁ = 248 Hz

current tension, T₁ = 350 N

fundamental frequency, f₂ = 256

The tension on the string to bring the guitar string into tune is calculated as;

v = \sqrt{\frac{T}{\mu} } \\\\f\lambda =  \sqrt{\frac{T}{\mu} } \\\\f^2\lambda^2 = \frac{T}{\mu} \\\\f^2 =  \frac{T}{\mu \lambda^2}\\\\let \ {\mu \lambda^2} = k\\\\f^2 =\frac{T}{k} \\\\k = \frac{T}{f^2} \\\\\frac{T_1}{f_1^2} = \frac{T_2}{f_2^2}\\\\T_2 = \frac{T_1 f_2^2}{f_1^2} \\\\T_2 =  \frac{350 \times  256^2}{248^2} \\\\T_2 = 372.95 \ Hz

Therefore, the tension to bring the guitar string into tune is 372.95 Hz.

3 0
3 years ago
Burning fossil fuels causes more air pollution than soil erosion, dust storms, and forest fires. true or false
hoa [83]
The answer is True

Burning fossil fuels DOES causes more air pollution than soil erosion, dust storms, and forest fires
8 0
3 years ago
Read 2 more answers
A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more tha
Liono4ka [1.6K]

Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π      where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π  time for A to again catch B

N = 1.39 * 24700 Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π      where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π  time for A to again catch B

N = 1.39 * 24700 Π / (4200 Π) = 8.2   laps

A will make 8 but not 9 rounds before catching B

6 0
2 years ago
Select the correct answer.
Gelneren [198K]

Answer: It's b and c I got it right

Explanation:

Hope this helped!!!! :)

8 0
3 years ago
A floating object oscillates up and down 2 complete cycles in 1 second as a water wave of wavelength 5 meters passes by. The spe
Elena-2011 [213]

Answer:

10 m/s

Explanation:

The speed of a wave is given by

v=\lambda f

where

\lambda is the wavelength

f is the frequency

For the wave in this problem,

- The frequency is given by the number of oscillations per second, so

f=\frac{2 cycles}{1 s}=2 Hz

- The wavelength is

\lambda=5 m

So, the wave speed is

v=(5 m)(2 Hz)=10 m/s

3 0
3 years ago
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