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kotykmax [81]
3 years ago
6

A negative number raised to an odd power is______ negative.

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0
It’s A. I hope that helps
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Help this test is due tonight! *no links please*
Doss [256]
I think transition, reflection, transition, and reflection.
6 0
3 years ago
Given the following 2 equations, state whether these equations are parallel, perpendicular, or neither.
stiks02 [169]

Answer:

Neither

Explanation:

The slope-intercept form of the equation of a line is generally given as;

y=mx+b

where m = the slope of the line

b = the y-intercept of the line

Two lines are said to be parallel if they have the same slope. Looking at the two given equations below, we see that the slope of the 1st one, 5/7, is different from the slope of the 2nd one, 7/5;

\begin{gathered} y=\frac{5}{7}x+14 \\ y=\frac{7}{5}x-20 \end{gathered}

Two lines are said to be perpendicular if their slopes are negative reciprocals of each other, let's go ahead and compare their slopes;

\begin{gathered} m_1=\frac{5}{7} \\ m_2=\frac{7}{5} \\ \therefore m_2=\frac{1}{m_1_{}} \end{gathered}

So the two lines are not perpendicular to each other. It, therefore, means that the correct answer will be Neither.

3 0
1 year ago
In one school day activity, ¾ of 24 girls wore a mini skirt for their presentation. How many girls wore mini skirt? (Use AGONSA.
yKpoI14uk [10]

Answer:

18

Step-by-step explanation24/0.75 is 18

6 0
3 years ago
Read 2 more answers
Give the slope of y- 4 = 5(x - 2) and a point on the line.
ValentinkaMS [17]

Answer:

<h2>B. The slope is 5 and (2, 4) is on the line.</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point</em>

<em />

We have the equation:

y-4=5(x-2)

Therefore

<em>m = 5</em>

<em>(x₁, y₁) = (2, 4)</em>

<em />

5 0
4 years ago
A ball is thrown upward with an initial velocity of 96 ft/sec from a height 640 ft. Its height​ h, in​ feet, after t seconds is
olchik [2.2K]
Check the picture below.

thus is at 0 = -16t² + 96t +640,

\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40)&#10;\\\\\\&#10;0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t=&#10;\begin{cases}&#10;\boxed{10}\\&#10;-4&#10;\end{cases}

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0
4 years ago
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