What is the point-slope form of a line with slope-3 that contains the point
(10,-1)?
1 answer:
Answer:
y = - 3x + 29
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 3, thus
y = - 3x + c ← is the partial equation of the line
To find c substitute (10, - 1) into the partial equation
- 1 = - 30 + c ⇒ c = - 1 + 30 = 29
y = - 3x + 29 ← equation of line
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