There are 163 people going to the movies 5, 6 or 7 times per month
there are 133 people going more than 7 times
So in total, there are 163+133=196 people going to the movies at least 5 times a month.
In total there are 728 people in the experiment.
P(a person goes at least 5 times per month)=n(people going at least 5 times)/n(people in the experiment)
= 196/728=0.269
Answer:
The answer is 13, please let me know if I am wrong
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
3.5 feet
Step-by-step explanation:
The question isn't formatted properly.
We have:
<em>(x + 6) feet on each side of the square
</em>
<em>(3x + 6) feet horizontally on the rectangle
</em>
<em>(x - 1) feet vertically on the rectangular</em>
<em />
First, we need to determine the perimeter of the square:
![Perimeter = 4 * Length](https://tex.z-dn.net/?f=Perimeter%20%3D%204%20%2A%20Length)
![Perimeter = 4 * (x + 6)](https://tex.z-dn.net/?f=Perimeter%20%3D%204%20%2A%20%28x%20%2B%206%29)
![Perimeter = 4x + 24](https://tex.z-dn.net/?f=Perimeter%20%3D%204x%20%2B%2024)
Next, we determine the perimeter of the rectangle
![Perimeter = 2(Length + Width)](https://tex.z-dn.net/?f=Perimeter%20%3D%202%28Length%20%2B%20Width%29)
![Perimeter = 2(3x + 6 + x - 1)](https://tex.z-dn.net/?f=Perimeter%20%3D%202%283x%20%2B%206%20%2B%20x%20-%201%29)
![Perimeter = 2(3x + x+ 6 - 1)](https://tex.z-dn.net/?f=Perimeter%20%3D%202%283x%20%2B%20x%2B%206%20%20-%201%29)
![Perimeter = 2(4x+ 5)](https://tex.z-dn.net/?f=Perimeter%20%3D%202%284x%2B%205%29)
![Perimeter = 8x+ 10](https://tex.z-dn.net/?f=Perimeter%20%3D%208x%2B%2010)
Equate both perimeters:
![8x + 10 = 4x + 24](https://tex.z-dn.net/?f=8x%20%2B%2010%20%3D%204x%20%2B%2024)
Collect Like Terms
![8x - 4x = 24 - 10](https://tex.z-dn.net/?f=8x%20-%204x%20%3D%20%2024%20-%2010)
![4x = 14](https://tex.z-dn.net/?f=4x%20%3D%20%2014)
Solve for x
![x = 14/4](https://tex.z-dn.net/?f=x%20%3D%2014%2F4)
![x = 3.5](https://tex.z-dn.net/?f=x%20%3D%203.5)
Answer:
- f(2) = 0.5(2) +3.4
- f(3.5) = 0.5(3.5) +3.4
- f(15) = 0.5(15) +3.4
- f(21.3) = 0.5(21.3) +3.4
Step-by-step explanation:
Put the given weight where x is in the function definition. You're only asked for the expression, not its value.
- f(2) = 0.5(2) +3.4
- f(3.5) = 0.5(3.5) +3.4
- f(15) = 0.5(15) +3.4
- f(21.3) = 0.5(21.3) +3.4
Step-by-step explanation:
Here n = 8 (even number)
![\therefore \: \frac{n}{2} = \frac{8}{2} = 4 \\ \\\&\:\: \frac{n}{2} + 1 = 4 + 1 = 5 \\ \\ hence \: \\ median = \frac{ {4}^{th} term + {5}^{th} term}{2} \\ \\ \therefore \: 49 = \frac{x - 1 + x + 1}{2} \\ \\ \therefore \: 49 = \frac{2x}{2} \\ \\ \therefore \: 49 = x \\ \\ \huge \purple { \boxed{\therefore \: x = 49}}](https://tex.z-dn.net/?f=%20%5Ctherefore%20%5C%3A%20%20%5Cfrac%7Bn%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B8%7D%7B2%7D%20%20%3D%204%20%5C%5C%20%20%5C%5C%5C%26%5C%3A%5C%3A%20%20%20%5Cfrac%7Bn%7D%7B2%7D%20%20%2B%201%20%3D%204%20%2B%201%20%3D%205%20%5C%5C%20%20%5C%5C%20hence%20%5C%3A%20%20%5C%5C%20median%20%3D%20%5Cfrac%7B%20%7B4%7D%5E%7Bth%7D%20term%20%2B%20%20%7B5%7D%5E%7Bth%7D%20term%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%2049%20%3D%20%20%5Cfrac%7Bx%20-%201%20%2B%20x%20%2B%201%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%2049%20%3D%20%20%5Cfrac%7B2x%7D%7B2%7D%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20%2049%20%3D%20x%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Cpurple%20%7B%20%5Cboxed%7B%5Ctherefore%20%5C%3A%20x%20%3D%2049%7D%7D)