Answer:
3.1 seconds
Step-by-step explanation:
The time it will hit the ground is when the <em>height is equal to 0</em>. So we plug in 0 in h and solve the quadratic equation for t.
We will use the quadratic formula [ ] to solve this.
a is -16
b is 40 , and
c is 30.
plugging these into the formula we get:
Since time cannot be negative, we take t = 3.1 as the value
So it will take 3.1 seconds to hit the ground (target)
Answer:
see the attachment for a graph
Step-by-step explanation:
The vertex of f(x) is (0, 0). The transformation g(x) = f(x -h) +k moves the vertex to (h, k). That is, the graph is translated right by h units, and up by k units.
Your transformation has h = -2, and k = -4. That is, the original graph is translated left 2 units and down 4 units. The result is the blue curve in the attachment.
Answer:
(a) The percentage of women who are taller than 64 inches is 50%.
(b) The percentage of women whose heights are between 60.6 inches and 67.4 inches is 68.26%.
(c) The percentage of women whose heights are between 57.2 inches and 70.8 inches is 95.44%.
(d) The percentage of women whose heights are between 57.2 inches and 67.4 inches is 65.48%.
Step-by-step explanation:
Let <em>X</em> = heights of college women.
It is provided that the heights of college women (<em>X</em>) follows a Normal distribution.
The mean and standard deviation of the heights of college women are:
*Use the standard normal table for the probabilities.*
(a)
Compute the proportion of women who are taller than 64 inches as follows:
The percentage is: 0.50 × 100 = 50%.
Thus, the percentage of women who are taller than 64 inches is 50%.
(b)
Compute the proportion of women whose heights are between 60.6 inches and 67.4 inches as follows:
The percentage is: 0.6826 × 100 = 68.26%.
Thus, the percentage of women whose heights are between 60.6 inches and 67.4 inches is 68.26%.
(c)
Compute the proportion of women whose heights are between 57.2 inches and 70.8 inches as follows:
The percentage is: 0.9544 × 100 = 95.44%.
Thus, the percentage of women whose heights are between 57.2 inches and 70.8 inches is 95.44%.
(d)
Compute the proportion of women whose heights are between 57.2 inches and 67.4 inches as follows:
The percentage is: 0.6548 × 100 = 65.48%.
Thus, the percentage of women whose heights are between 57.2 inches and 67.4 inches is 65.48%.