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SCORPION-xisa [38]
3 years ago
5

Complete the steps for x. 5/6x- 1/5x =19 5/6x- 1/5x =19 ?/30x=19

Mathematics
2 answers:
dybincka [34]3 years ago
8 0

Answer:

x = 30

Step-by-step explanation:

5/6x- 1/5x =19

Get a common denominator of 30

5/6x * 5/5  - 1/5x * 6/6 = 19

25/30x - 6/30x = 19

19/30x = 19

Multiply each side by 30/19

19/30x * 30/19  = 30/19 * 19

x = 30

love history [14]3 years ago
8 0

Answer:

5/6x- 1/5x =19

5/6x- 1/5x =19

?/30x=19

19/30x = 19

x = 19 / 19/30

x = 19 * 30/19

x = 30

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Answer:

Equation:

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

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r =  \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }

r =  \sqrt{ {(5 -  - 1)}^{2} + {( - 2- - 1)}^{2} }

r =  \sqrt{ {(6)}^{2} + {( - 1)}^{2} }

r =  \sqrt{ 36+ 1 }  =  \sqrt{37}

The equation of the circle is given by:

(x-h)^2 + (y-k)^2 =  {r}^{2}

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

(x- - 1)^2 + (y-1)^2 =  {( \sqrt{37}) }^{2}

(x + 1)^2 + (y - 1)^2 = 37

We expand to get:

{x}^{2}  + 2x  + 1 +  {y}^{2}  - 2y + 1 = 37

{x}^{2}   +  {y}^{2} +  2x  - 2y +2 - 37= 0

{x}^{2}   +  {y}^{2} +  2x  - 2y   -  35= 0

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We can choose any point for x and solve for y or vice-versa

When y=0,

{x}^{2}   +  {0}^{2} +  2x  - 2(0)  -   35= 0

{x}^{2}   +2x   -   35= 0

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x = 5 \: or \: x =  - 7

The point (5,0) and (-7,0) lies on the circle.

When x=0

{0}^{2}   +  {y}^{2} +  2(0)  - 2y   -  35= 0

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