First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
2x^2 +11
Step-by-step explanation:
f(x) = 3x^2 + 2 and g(x) = x^2 – 9
(f – g)(x) = 3x^2 + 2 -( x^2 – 9)
Distribute the minus sign
3x^2 + 2 - x^2 + 9
Combine like terms
2x^2 +11
T b
0 70
1 66
2 62
3 58
4 54
This is not a proportional relationship because the ratios are not equivalent.
1/66 (t/b) is not equivalent to 2/62 (t/b).
Answer:
D - The slope from point O to point A is three times the slope of the line from point A to point B.
Answer:
A
Step-by-step explanation:
What we need to know simply is the time taken for both trips. We know the car spent 6 hours on the first leg, that is settled.
What we do not know is the time spent on the second leg. To get the time spent on the second leg of the journey, we only need to get the total distance divided by the speed.
We can get the distance using the first part of the question. The time is 6 hours and the speed is x miles per hour, the total distance is this 6x miles.
Now we need to know the time spent on the second leg of the journey. We know that the distance is the same. Hence the time spent is 6x/y where y is the speed for the second leg and 6x is the length of each leg
Now the total time spent is thus (6x/y +6) hours. We need to however convert this to minutes. We do this by multiplying by 60
(6x/y + 6) * 60
