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siniylev [52]
3 years ago
13

Will you guys help me please

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0
1.2, 1.23, 2.31, 3.2
marusya05 [52]3 years ago
7 0
How you do this is you go from left to right with each one, and figure out which number is greater. For this particular problem the answer will be,

1.2   1.23   2.31  3.2
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BRAINLIESTTTTTT ASAPPPP<br> PLEASE ANSWER MY QUESTION
yawa3891 [41]
The red line is represented by y ≥ -3x + 3.

The blue line is represented by y < 3/2x - 6.

A) In this system of inequalities, there is one solid line and one dashed line.

The solid line is the inequality y ≥ -3x + 3 because it has the symbol greater than or equal to. The "equal to" part of the symbol is important because it means that any coordinate located on the solid line is a solution.

However, the inequality y < 3/2x - 6 is a dashed line because it does not have "equal to." This makes the inequality a dashed line which means that all coordinates on it will not be a solution to the inequality.

In the inequality y ≥ -3x + 3, the shading is above the line. This means that all coordinates within the line and shaded area above the line will be a solution to the inequality.

In the inequality y < 3/2x - 6, the shading is below the line. This means that all coordinates within the shared area of the line will be a solution to the inequality. However, since y is not less than or EQUAL TO, all coordinates within the dashed line is not a solution to the inequality.

The solution area, where a coordinate is a solution to
both inequalities, is where the shaded areas of both inequalities overlap.

B) The point (-6, 3) is a not solution to both of the inequalities because it is not within the shared areas of the two inequalities.

Substitute the coordinate (-6, 3) in the inequality y < 3/2x - 6.

y < 3/2x - 6

3 < 3/2(-6) - 6

3 < -9 - 6

3 < -15

This is not true because a negative number cannot be greater than a positive number. Therefore, this proves that the coordinate (-6, 3) is not a solution for the inequality y < 3/2x - 6.

Check if the coordinate fits for the other inequality.

y ≥ -3x + 3

3 ≥ -3(-6) + 3

3 ≥ 18 + 3

3 ≥ 21

This is also not true because 3 is not greater than or equal to 21. Therefore, this coordinate is not a solution to the inequality y ≥ -3x + 3.

The coordinate (-6, 3) is not a solution for the system of inequalities because it is not a solution for both inequalities.

7 0
4 years ago
What is the quotient and remainder of 5,897 divide by 24
mr Goodwill [35]
The answer is 245 remainder 17
7 0
3 years ago
Read 2 more answers
The ratio 2.5 metres to 60 centimetres can be written in the form 1:n find the valur of n
Maslowich

Answer:

The value of n is \frac{6}{25}

Step-by-step explanation:

we know that

1 m=100 cm

step 1

Convert 2.5 m to cm

2.5 m=2.5*100=250 cm

step 2

Find the ratio

\frac{250}{60}=\frac{25}{6}

Divide by 25 both numerator and denominator

\frac{1}{\frac{6}{25}}

therefore

The value of n is \frac{6}{25}

8 0
4 years ago
Please answer this thank you.​
adoni [48]

Answer:

√250 = 5√10

a= 5

b= 10

4 0
3 years ago
A ship at position (1, 0) on a nautical chart (with north in the positive y direction) sights a rock at position (7, 5). What an
Romashka-Z-Leto [24]

Answer:

0.69473828 radians east of north.

Step-by-step explanation:

Interpreting the information given on a Cartesian plane, the position of the ship will be (1,0) and that of the rock will be (7,5). Connecting the point (1,0) and (7,5) with a line and dropping a perpendicular line from point (7,5) to the x-axis to intersect the x-axis at (7,0), will form a right-triangle with base length 6 units and a height of 5 units.

<u>Finding the base length from points (1,0) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-1)²

d= √6²

d=6 units

<u>Finding the height from points (7,5) and (7,0)</u>

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(7-7)² + (0-5)²

d=√-5²

d=√25

d=5 units

So you now have a right triangle with base length 6 units and height 5 units.

To get the bearing of rock from ship position you apply the formula for tangent of an angle

Tan Ф = length of opposite side/length of adjustment side

TanФ=5/6

Tan Ф =0.83333333333

Tan⁻¹ (0.83333333333) =0.69473828 radians east of north.

3 0
3 years ago
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