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4 years ago

Can someone please help me with number 1?

Mathematics

2 answers:

sattari [20]4 years ago

5 0

A population is a lot of data to handle but a sample gets a good variety of answers so sample is easier and quicker than a population!

Archy [21]4 years ago

4 0

A sample would be easier then having to survey the entire population due to the amount of people in a population.

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Identify the scale factor for the dilation below if ABCD is the preimage.

-BARSIC- [3]

AHHHHHHHHHHHHHHHHHHHHH

8 0

3 years ago

Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.

lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

$PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ$

Likewise:

$\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ$

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

$m\angle PAC=m\angle PAB+m\angle BAC$

Likewise:

$m\angle QAB=m\angle QAC+m\angle BAC$

Since ∠QAC ≅ ∠PAB:

$m\angle PAC=m\angle QAC+m\angle BAC$

And by substitution:

$m\angle PAC=m\angle QAB$

Thus:

$\angle PAC\cong \angle QAB$

Then by SAS Congruence:

$\Delta PAC\cong \Delta BAQ$

And by CPCTC:

$PC\cong BQ$

5 0

3 years ago

Read 2 more answers

Kyle and Andrea were asked to make a list of prime numbers.

ozzi

They are both correct.

8 0

3 years ago

Match the equation with the step needed to solve it.

ivanzaharov [21]

Send more info , you have to match the 3 with 2

7 0

3 years ago

What is the quotient of the complex number 4-3i divided by its conjugate?

almond37 [142]

Answer: C. $\frac{7}{25}-\frac{24}{25}i$

Step-by-step explanation:

1. You have the following division:

$\frac{4-3i}{4+3i}$ (As you can see, to find the conjugate of 4-3i you must change the sign between the terms).

2. To solve this division, you must multiply the numerator and the denominator by the conjugate of the denominator, as following:

$=\frac{(4-3i)}{(4+3i)}\frac{(4-3i)}{(4-3i)}=\frac{16-12i-12i+9i^{2}}{16-9i^{2}}$

3. Keeping on mind that $i^{2}=-1$ , you have:

$=\frac{16-12i-12i+9(-1)}{16-9(-1)}$

4. Simplifying:

$=\frac{7-24i}{25}=\frac{7}{25}-\frac{24}{25}i$

5. The result is:

$\frac{7}{25}-\frac{24}{25}i$

3 0

4 years ago