58-180=122 x=122 hope this helps have a nice nite!
Answer:
-1*70
Step-by-step explanation:
-1*70=-71
Answer:
Answer:
£3692
Step-by-step explanation:
A = p(1 + r/n)^nt
Where,
A = future value
P = principal = £2350
r = interest rate = 4.2% = 0.042
n = number of periods = 1(annual)
t = time = 4 years
A = p(1 + r/n)^nt
= 2350(1 + 0.042/1)^1*4
= 2350(1 + 0.042)^4
= 2350(1.042)^4
= 2350(1.5789)
= 2770.42
A = £2770.42
Total years = 10
Remaining years = 10 – 4
= 6 years
Remaining 6 years
P = £2770.42
r = 4.9% = 0.049
n = 1
t = 6
A = p(1 + r/n)^nt
= 2770.42(1 + 0.049/1)^1*6
= 2770.42(1 + 0.049)^6
= 2770.42(1.049)^6
= 2770.42(1.3325)
= 3691.59
A = £3691.59
Approximately £3692
Thank you!
I say left because you have a straight line, i goes through 0,0 and every time it goes over 1 and up by 3.
<h2>
Hello!</h2>
The answer is:

<h2>
Why?</h2>
To solve the problem we need to add/subtract like terms. We need to remember that like terms are the terms that share the same variable and the same exponent.
For example, we have:

We have that we were able to add just the terms that were sharing the same variable and exponenr (x for this case).
So, we are given the expression:

Hence, the answer is:

Have a nice day!