I need help on how to find out this answer asap !!!

Mathematics

1 answer:

amm18123 years ago

6 0

<h2>Answer:</h2><h2>I think 45 is your answer buddy...!!</h2>

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Three business associates are at their favorite local café for lunch. They have finished their meals and just received their bil

telo118 [61]

Customer #2 has the smallest total bill, including tax and tip.
Choice A, 1.06b + 0.16(1.06b), is correct.
Customer 3's bill is approximately 10% less than customer 1's bill.
Customer 2 leaves the bigger tip.

For customer #1:
(1.06(12.95))(1.15) = 15.79; the tip is 0.15(1.06(12.95)) = 2.06.
For customer #2:
1.06x = 11.65; x = 10.99; 20% tip = 0.2(10.99) = 2.20; total = 11.65+2.20 = 13.85.
For customer #3:
1.06(11.50) + 0.18(11.50) = 14.26; the tip is (0.18)(11.50) = 2.07.

Customer 3 spends 15.79-14.26 = 1.53 less than customer #1, which is 1.53/15.79 = 0.097 ≈ 10% less.

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3 years ago

Michael sold 23 of his CDs and purchased 16 more.

aleksley [76]

25-16=9
9+23=32
He had 32 CDs to begin with

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3 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$