Answer:
A
Explanation:
First, we're given that the atmospheric pressure is 744.8 mmHg. However, this includes the pressure of the Zinc and the pressure of the water; we only want the pressure of the water, so subtract its pressures (23.8 mmHg) from 744.8 mmHg: 744.8 - 23.8 = 721 mmHg.
Now, we can use the ideal gas law: PV = nRT.
- the pressure P is 721 mmHg
- the volume V is 7.80 L
- the moles n of Zinc is what we want to find in order to calculate the mass
- the gas constant R is 62.36 L mmHg / (mol K)
- the temperature T is 25.0°C, or 25.0 + 273 = 298 K
Plug all these in:
PV = nRT
(721 mmHg) * (7.80 L) = n * (62.36) * (298 K)
n ≈ 0.303 mol Zn
We need to convert this to grams, so use the molar mass of Zinc, which is 65.38 g/mol:
Thus, the answer is A.
B
1 mile=4 poles
if 5 poles pass by than she´s going around 1.25 miles per min
rounded up = 1.3 mil/min
Answer:
All the option are correct
Explanation:
The ocean currents have been associated with past climatic shifts during critical periods (for example, the ice ages), where modifications in water circulation might have caused important climatic changes.
From a biological point of view, the ocean currents may be associated not only with the climate but also biogeochemical cycles through modifications in the distribution of heat and freshwater. Thus, the changes in ocean circulation may produce biogeographical shifts by affecting the local climate. The importance of ocean currents in affecting biodiversity is also represented by the equilibrium of coral reef ecosystems, where this equilibrium is broken up by factors such as transport of pollutants, temperature conditions, etc., which are known to alter thermosensitive coral species.
Answer: 25.89g of O2 (g)
Explanation:
We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2
1 mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g
1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g
According to the equation;
245.1g of KCLO3 produces 96g of O2 (g)
If 1g of KCLO3 produces 96÷245.1 of O2 (g) from heating.
66.1g of KCLO3 would produce; 96÷245.1 x 66.1 = 25.89g of O2 (g) from heating.