Answer:
C
Explanation:
C) an atom with an atomic number of 18
True
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Pb(NO₃)₂(aq) + 2NaI(aq) → 2NaNO₃(aq) + PbI₂(s)
PbI₂ (the precipitate)
Answer:
a) 21 bonds , and 4 bonds
b) bond angles , a < 109.5° , b ≈ 120° c < 109.5° d,e < 120° f ≈ 120° g ≈ 109.5°
c) 6 carbon atom are sp² hybridized
d) two carbon atoms are sp³ hybridized,
two oxygen atoms are sp³ hybridized
Nitrogen is not sp³ hybridized , it has sp² hybridization
e) vitamin B6 exhibit delocalized bonding, because the three double bond in ring are delocalized over 5 carbon atoms and one nitrogen atom , they are formed due to 6 p orbitals of 5 carbons and 1 Nitrogen atom. The bonding in vitamin B6 is similar to the Benzene.
Explanation:
Answer:
We need 4.28 grams of sodium formate
Explanation:
<u>Step 1:</u> Data given
MW of sodium formate = 68.01 g/mol
Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L
pH = 3.74
Ka = 0.00018
<u>Step 2:</u> Calculate [base)
3.74 = -log(0.00018) + log [base]/[acid]
0 = log [base]/[acid]
0 = log [base] / 0.42
10^0 = 1 = [base]/0.42 M
[base] = 0.42 M
<u>Step 3:</u> Calculate moles of sodium formate:
Moles sodium formate = molarity * volume
Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles
<u>Step 4:</u> Calculate mass of sodium formate:
Mass sodium formate = moles sodium formate * Molar mass sodium formate
Mass sodium formate = 0.063 mol * 68.01 g/mol
Mass sodium formate = 4.28 grams
We need 4.28 grams of sodium formate
