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grigory [225]
3 years ago
7

Work out the time taken, in minutes, for a 68km journey at an average speed of 85km/h​

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

48 minutes

Step-by-step explanation: Time taken is distance divided by speed, so 68/85 is 0.8. 0.8 is equal to 4/5. 4/5 of an hour is 48 minutes.

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Answer: ~27.5

Step-by-step explanation:

I don't know about all the geometry terms, but since a line is 180°, and SE makes 1 right angle (90°), the other side is also 90° (180-90=90).

This means you have a right triangle with sides 15 and 23 and unknown hypotenuse AS.

Pythagorean Theorem: a^2 + b^2 = c^2

(15^2) + (23^2) = AS^2

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AS = 27.459

8 0
2 years ago
What is 2.24 rounded to the nearest tenth?
quester [9]
One tenth is 0.1.  Therefore, the answer has to be 2.x.  Since 4 is less than 5, the 2 remains the same.  The answer is 2.2.  
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2 years ago
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Combine these radicals<br> 3V2-5V2<br><br> Plz help<br> Will give Brainlyest
lukranit [14]

Answer:

b

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5 0
3 years ago
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Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 End
IgorC [24]

Answer:

\approx \frac{11}{40}

Step-by-step explanation:

Juice squeezed from first orange = \frac{4}{17} = 0.235

Juice squeezed from second orange = \frac{3}{10} = 0.3

Juice squeezed from third orange = \frac{9}{20} = 0.45

Juice squeezed from fourth orange = \frac{3}{11} = 0.27

Juice squeezed from fifth orange = \frac{7}{15} = 0.47

Total juice squeezed from all the five oranges = 0.235 + 0.3 + 0.45 + 0.27 + 0.47 = 1.725

Total juice to be squeezed = 2 cups

More juice required = 2 - 1.725 = 0.275 \approx \frac{11}{40}

Therefore, to make it 2 cups of orange juice for the family, about \approx \frac{11}{40} cups of more juice is required.

8 0
3 years ago
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Let A = R−{0}, the set of all nonzero real numbers, and consider the following relations on A × A. Decide in each case whether R
andre [41]

Answer:

Step-by-step explanation:

Let A = R−{0}, the set of all nonzero real numbers, and consider the following relations on A × A.

Given that (a,b) R (c,d) if ad=bc

Or (a,b) R (c,d) if determinant

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =0

a) Reflexive:

We have (a,b) R (a,b) because ab-ab =0 Hence reflexive

b) Symmetric

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Or da-cb =0 or cb-da =0 Hence (c,d) R(a,b). Hence symmetric

Download docx
5 0
3 years ago
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