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AysviL [449]
3 years ago
5

How many exterior angles does a triangle have at each vertex

Mathematics
2 answers:
zepelin [54]3 years ago
8 0

Answer:

The answer will be six

Step-by-step explanation:

Molodets [167]3 years ago
7 0
Every triangle has 6 exterior angles, two at each vertex.
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If the perimeter of a square is 20, find the length of a diagonal
avanturin [10]

Answer:

7.07

Step-by-step explanation:

<h2><u>Length</u></h2>

a square has equal length on each side

hence is the perimeter is 20 it means that :

each side is 20/4 = 5

we can make a diagonal line which create 3 right angled triangles

2 sides of the triangle are 5 , this is the base and the height

to find the length we can make use of the Pythagoras theorem

c^2 = a^2 + b^2

c is the hypotenuse ( the diagonal;)

a and b are the opposite and adjacent

hence :

c^2 = 5 ^2 + 5^2

c^2 = 50

c = \sqrt{50}

c = 7.071

to 3sf

<h3><u>diagonal length  = 7.07</u></h3>

6 0
3 years ago
A) NO CHANGE<br> B) City in the 1860s,<br> C) City, in the 1860s,<br> D) City in the 1860s
Oliga [24]

The correct option is B. City in the 1860s.

Conference In Two Years is the full form of CITY, CITY stands for Conference In Two Years, or Conference In Two Years is the complete name of the given abbreviation.

Any person whose salary is payable, in whole or in part, from the City treasury is referred to as a "City Official," as is any employee, officer, or elected official of the City.

Life as it is lived in a city, especially when compared to that of a small town, hamlet, etc.; the way of life thought to be typical of city dwellers.

Disclaimer

City in the 1860s- stole more than $30 millions.

Choose the correct option

A) NO CHANGE

B) City in the 1860s,

C) City, in the 1860s,

D) City in the 1860s

Learn more about City here

brainly.com/question/237028

#SPJ4

4 0
1 year ago
If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro
yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

\Rightarrow f(x) = 2\cos x + e^{2x}

\Rightarrow f'(x) = -2\sin x + 2e^{2x}

And,

\Rightarrow f(2) = 2\cos 2 + e^{4}

\Rightarrow f'(2) = -2\sin 2 + 2e^{4}

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

\Rightarrow y-y_1=m(x-x_1)

\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)

\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})

The value of f(2.1) will be

\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})

\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})

\Rightarrow y=64.5946

According to given function, f(2.1) will be,

\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}

\Rightarrow f(2.1) = 65.6766

\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%

5 0
3 years ago
Please help me with this I will mark you brainliest
Zinaida [17]

AC=4.26 cm

Hope this helps you

7 0
3 years ago
-3 - 3х2 – 4x factor
Vlad1618 [11]

Answer:

-1 out of -3-X2-4x

Step-by-step explanation:

8 0
3 years ago
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