How many exterior angles does a triangle have at each vertex
2 answers:
You might be interested in
Standard reduction of order procedure: suppose there is a second solution of the form 
, which has derivatives
Substitute these terms into the ODE:
and replacing
, we have an ODE linear in 
:
Divide both sides by
, giving
and noting that the left hand side is a derivative of a product, namely
![\dfrac{\mathrm d}{\mathrm dx}[wx]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bwx%5D%3D0)
we can then integrate both sides to obtain
Solve for
:
Now
where the second term is already accounted for by
, which means 
, and the above is the general solution for the ODE.
Substitute these terms into the ODE:
and replacing
Divide both sides by
and noting that the left hand side is a derivative of a product, namely
we can then integrate both sides to obtain
Solve for
Now
where the second term is already accounted for by
f (x) = x ^ 4-x ^ 3 + x ^ 2-x
For this case what we can do is graph the function and see the behavior of it.
We have then that the function grows upwards (see attached image)
It has two cutting points with the x axis in:
x = 0
x = 1
Therefore, the other roots of the polynomial are imaginary.
Answer:
2 x intercepts appear on the graph of this polynomial function
For this case what we can do is graph the function and see the behavior of it.
We have then that the function grows upwards (see attached image)
It has two cutting points with the x axis in:
x = 0
x = 1
Therefore, the other roots of the polynomial are imaginary.
Answer:
2 x intercepts appear on the graph of this polynomial function