Answer:
Atomic mass of Ag-107 = 106.94 amu
Explanation:
Let the mass of Ag-107 be y
Since the mass ratio of Ag-109/Ag-107 is 1.0187, the mass of Ag-109 is 1.0187 times heavier than the mass of Ag-107
Mass of Ag-109 = 1.0187y
Relative atomic mass of Ag = sum of (mass of each isotope * abundance)
Relative atomic mass of Ag = 107.87
Abundance of Ag-107 = 51.839% = 0.51839
Abundance of Ag-109 = 41.161% = 0.48161
107.87 = (y * 0.51839) + (1.018y * 0.48161)
107.87 = 0.51838y + 0.49027898y
107.87 = 1.00865898y
y = 107.87/1.00865898
y = 106.94 amu
Therefore, atomic mass of Ag-107 = 106.94 amu
Answer:
Valence electrons are the most important electrons to an atom.
Explanation:
They will determine many of the atoms traits since they are involved in bonding with other atoms.
These transitional fossils serve as evidence to Darwin's Theory of Natural Selection as conserved traits are proven to survive the test of time. This also supports evolution in a way that is shows gradual change in traits of species over generations due to change in living conditions.
The Stereo microscope, also called a dissecting microscope, has two optical paths at slightly different angles allowing the image to be viewed three-dimensionally under the lenses. Stereo microscopes magnify at low power, typically between 10X and 200X.