4) would be your correct answer
Answer:
32.0 kJ
General Formulas and Concepts:
<u>Thermochemistry</u>
Specific Heat Formula: q = mcΔT
- q is heat (in J)
- m is mass (in g)
- c is specific heat (in J/g °C)
- ΔT is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>m</em> = 1.00 g
[Given] ΔT = 1.48 °C
[Given] <em>c</em> = 21.6 kJ/g °C
[Solve] <em>q</em>
<em />
<u>Step 2: Find Heat</u>
- Substitute in variables [Specific Heat Formula]: q = (1.00 g)(21.6 kJ/g °C)(1.48 °C)
- Multiply [Cancel out units]: q = (21.6 kJ/°C)(1.48 °C)
- Multiply [Cancel out units]: q = 31.968 kJ
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
31.968 kJ ≈ 32.0 kJ
Explanation:
Answer
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The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.
Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O ) = 0
2× ( Oxidation number of Al) +3(−2)=0
2× ( oxidation number of Al) +6
∴ Oxidation number of Al =+3