Answer:
8.44 atm
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 2.25 L
Initial temperature (T₁) = 350 K
Initial pressure (P₁) = 1.75 atm
Final volume (V₂) = 1 L
Final temperature (T₂) = 750 K
Final pressure (P₂) =?
The final pressure of the gas can be obtained as illustrated below:
P₁V₁/T₁ = P₂V₂/T₂
1.75 × 2.25 / 350 = P₂ × 1 / 750
3.9375 / 350 = P₂ / 750
Cross multiply
350 × P₂ = 3.9375 × 750
350 × P₂ = 2953.125
Divide both side by 350
P₂ = 2953.125 / 350
P₂ = 8.44 atm
Thus, the final pressure of the gas is 8.44 atm.
Answer:
36.2 K
Explanation:
Step 1: Given data
- Initial pressure of the gas (P₁): 8.6 atm
- Initial temperature of the gas (T₁): 38°C
- Final pressure of the gas (P₂): 1.0 atm (standard pressure)
- Final temperature of the gas (T₂): ?
Step 2: Convert T₁ to Kelvin
We will use the following expression.
K = °C +273.15
K = 38 °C +273.15 = 311 K
Step 3: Calculate T₂
We will use Gay Lussac's law.
P₁/T₁ = P₂/T₂
T₂ = P₂ × T₁/P₁
T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K
Answer is: the pressure in a vessel is 1.48 atm.
V(Cl₂) = 22.4 L; pressure of chlorine gas.
n(Cl₂) = 1.50 mol; amount of chlorine gas.
T = 0.00°C = 273.15 K; temperature.
a = 6.49 L²·atm/mol²; the constant a provides a correction for the intermolecular forces.
b = 0.0562 L/mol; value is the volume of one mole of the chlorine gas.
R = 0.08206 L·atm/mol·K, universal gas constant.
Van de Waals equation: (P + an² / V²)(V - nb) = nRT.
(P + 6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) · (22.4 L - 1.5 mol·0.0562 L/mol) = 1.5 mol · 0.08206 L·atm/mol·K · 273.15 K.
(P + 6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) = (1.5 mol · 0.08206 L·atm/mol·K · 273.15 K) ÷ (22.4 L - 1.5 mol · 0.0562 L/mol).
P + 0.029 atm = 33.62 L·atm ÷ 22.31 L.
P = 1.507 atm - 0.029 atm.
P = 1.48 atm; the pressure.
Answer:
add more types of plants
Explanation:are you kidding me i’m doing this stuff and i’m in 7th grade
Answer:
B.
Explanation:
the SI unit for density is the kilogram per Cubic meter
