They're all whole/natural numbers. The only difference is that one problem is in the form of currency. Anyhoo, you'll end up with the same answer. Currency, and an equation. The similarities are the factors, and the operations are the same.
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Wait before i answer what is the question like what do you want us to find?
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Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)
The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.
Step-by-step explanation:
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