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2 years ago

9

How do I divide 12 by 3 and get a mixed number .please help!!!!!!

1 answer:

kicyunya [14]2 years ago

4 0

Division doesn't always result in a mixed number. And you don't have
a choice . . . either it does or it doesn't.

If you divide 12 by 3, it doesn't. You get just plain 4 with no fraction.

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Absolute power of x minus 8 equals -5 solve

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Your answer is "x=3"!

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3 years ago

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expeople1 [14]

6 i believe but im not sure

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2 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

2 years ago

UkoKoshka [18]

Answer:

really easy its 180

Step-by-step explanation:

because you multiply 30 times 6 u get 180

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