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Aneli [31]
3 years ago
7

The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales

representatives make an average of 43 sales calls per week on professors. Several reps say that this estimate is too low. To investigate, a random sample of 29 sales representatives reveals that the mean number of calls made last week was 44. The standard deviation of the sample is 4.1 calls. Using the 0.050 significance level, can we conclude that the mean number of calls per salesperson per week is more than 43? H0: μ ≤ 43 H1: μ > 43 Compute the value of the test statistic. (Round your answer to 3 decimal places.)
Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

The critical region for α= 0.05 is Z > ± 1.645

The calculated value of Z= 1.100

Step-by-step explanation:

The null and alternate hypotheses are given

H0: μ ≤ 43

H1: μ > 43  one tail test

∝= 0.05

n= 29

Standard Deviation= s= 4.1

Mean = μ0 = 44

For one tail test the z value of α= ± 1.645

The critical region for α= 0.05 is Z > ± 1.645

The test statistic is given by

z=μ0-μ/ s/√n

Z= 44-43/4.1/√29

Z= 1/4.1/√29

Z= 1.100

Since the calculated value Z= 1.100 does not  fall in the critical region , We reject H0 and may conclude that the mean number of calls per salesperson per week is not more than 43

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Imagine you had 3 strips of paper that were 7 inches, 8 inches and 15 inches long. The 7 and 8 inch strips add to 15 inches, but those two smaller strips only form a straight line. We cannot pull them so a triangle forms. If we did, then the third side would be smaller than 15 inches. This is one way to get hands on to see why the triangle inequality theorem works.

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