Question

PLEASE HELP the vertex form of the equation of a parabola is y = (x - 3)2 + 36. what is the standard form of the equation?

Answer 1

Answer:

$\large \boxed{\sf \bf \ \ x^2-6x+45 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

You need to develop the expression.

$y=(x-3)^2+36\\\\=x^2-2 * 3 * x +3^2+36\\\\=x^2-6x+9+36\\\\=x^2-6x+45$

Thank you.