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3 years ago

PLEASE HELP the vertex form of the equation of a parabola is y = (x - 3)2 + 36. what is the standard form of the equation?

Mathematics

1 answer:

Sidana [21]3 years ago

8 0

Answer:

$\large \boxed{\sf \bf \ \ x^2-6x+45 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

You need to develop the expression.

$y=(x-3)^2+36\\\\=x^2-2 * 3 * x +3^2+36\\\\=x^2-6x+9+36\\\\=x^2-6x+45$

Thank you.

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3 years ago

Which of the above polynomials is a 5th degree trinomial?

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Easy

5th degree means highest power is 5 so must have x^5

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3 years ago

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alexdok [17]

Answer:

Step-by-step explanation:

Using the compound interest formula to calculate the amount compounded after 10years.

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3 years ago

Make n the subject of the formula

kogti [31]

Answer:

$\mathsf{ \frac{m + 21}{5} = n }$

Step-by-step explanation:

To make "n" the subject of the formula, rearrange the formula so it begins with " n = "

To isolate the variable "n", you need to inverse the other terms on that side of the equation where "n" really is.

=> m = 5n - 21

there's a "-21" next to "5n", inverse of subtraction is addition, so add 21 on both sides of the equation.

=> m + 21 = 5n - 21 + 21

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There's also a 5 attached to n, that means the multiplication of n with 5, the inverse of multiplication is division, so dividing both sides of the equation by 5

$\mathsf{ \frac{m + 21}{5} = n }$

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3 years ago