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kramer
2 years ago
5

Need help asap.pls and thanks

Mathematics
1 answer:
love history [14]2 years ago
6 0

Answer:

your speed is 135 mph

Step-by-step explanation:

                                   

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Use the equation below to find d, if r=45 and t = 3.<br> d=rt
Elden [556K]

Answer:

d= 135

Step-by-step explanation:

45*3

6 0
2 years ago
a bar graph shows that sport books received 9 votes. if the scale is 0 to 20 by twos, where should the bar end for the books
leva [86]
If sport books recieved 9 votes then they would be in the middle of 8 and 10 on the bar graph. If you want to know where the bar should end it would be 10.
Hope helps!
6 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
2 years ago
What are the factors of 54 and 90?
amid [387]
9 and 3 are the only common factors between 54 and 90
8 0
3 years ago
Read 2 more answers
How<br>Solve The D. E<br><br> dy/dx=2x^5 y^3 - 4y/x<br><br>​
Pachacha [2.7K]
Dy/dx (2x⁵ y³ - 4y/x)

dy/dx (2y³ x⁵ - 4y/x)

dy/dx ( 2y³ x⁵ ) - dy/dx (4y/x)

= 2y³ 5x⁴ - (-4y × 1/x²)

=
10x⁶ y³ + 4y
-------------------
x²

3 0
3 years ago
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