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Elanso [62]
2 years ago
8

One pipe can fill a tank in 12 hours and another can fill the tank in 8 hours. How long would it take to fill the tank using bot

h of the pipes
Mathematics
1 answer:
JulijaS [17]2 years ago
7 0

Answer:

It will take 4 hours and 48 minutes with both pipes.

Step-by-step explanation:

Add their rates of filling

1st pipe's rate = ( 1 tank ) / ( 12 hrs )

2nd pipe's rate = ( 1 tank ) / ( 8 hrs )

Let, t = hrs to fill tank using both pipes

(1 / 12) + (1 / 8) = (1 / t)

Multiply both sides by 24t

2t + 3t = 24

5t = 24

t = 4.8

0.8 x 60 = 48

It will take 4 hours and 48 minutes with both pipes

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When q = 15, r = 4<br> Find q when r = 7
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Answer:

q = 18 ?

Step-by-step explanation:

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a wildlife photographer photographs a crocodile and then paddles against a river current for 6 km. Then, hoping to photograph a
rusak2 [61]

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3 years ago
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The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an
solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable <em>X</em> can be defined as the pregnancy length in days.

Then, from the provided information X\sim N(\mu=268, \sigma^{2}=12^{2}).

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ <em>z</em> = 1.23

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ <em>z</em> = -1.645

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

8 0
2 years ago
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