Factor this equation 4x^2+12x-7

1 answer:

3 0

$4x^2+12x-7=0\\\\a=4;\ b=12;\ c=-7\\\Delta=b^2-4ac\\\\\Delta=12^2-4\cdot4\cdot(-7)=144+112=256 \ \textgreater \ 0\\\\therefore\\x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{256}=16\\\\x_1=\dfrac{-12-16}{2\cdot4}=\dfrac{-28}{8}=\boxed{-\dfrac{7}{2}}\\\\x_2=\dfrac{-12+16}{2\cdot4}=\dfrac{4}{8}=\boxed{\dfrac{1}{2}}$

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Which statement describes a number with the smallest absolute value?

Snezhnost [94]

I believe C. The temperature is -23 degrees.

This is because, a negative (absolute value) becomes positive

Which would lead for |-23| to end up being |23|

Anytime a negative absolute value is placed, it becomes a positive and a positive stays positive.

So the smallest would be C then B later D and at last A

4 0

3 years ago

2x + y = 3

sergejj [24]

Hey there!

First, multiply the second equation by -2 as the problem states. When you multiply the second equation by -2, you get:

-2x+4y=2

Now, add this equation to the first equation in which you simply combine like terms:

2x+y=3

-2x+4y=2

5y= 5

In conclusion, the correct answer would be the first choice.