Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 3x – 5y = 9 is m = 3<span>/5. Therefore, the slope of the line parallel to this line would have to be </span>m = 3<span>/5.</span>
Answer:
In technical terms, the slope of the line is the change in y over the change in x. But I just like to think of it as rise over run. To find the slope of the line, pick two points on the line.
Answer:
0.5 m/s
Falling at 32 feet/s
Step-by-step explanation:
For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.
For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.
Let me know if you have any questions!
Answer:
The correct system when solved is (-1, -2)
Step-by-step explanation:
Using (-1, -2)
x = -1
y = -2
x + 5y = -11
-1 + 5× -2 = -11
2x + 5y = -12
2× -1 + 5× -2 = -12