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3 years ago

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A positive integer with exactly two different divisors greater than 1 must be(A) a prime(B) an even integer(C) a multiple of 3(D

) the square of a prime(E) the square of an odd integer

1 answer:

marta [7]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find the value of x and the measure of the angel labeled 6x. A. X=5; angle measure is 42 B. X=5; angel measure is 72 C. X= 5; an

Sergeu [11.5K]

Answer:

x = 5

angle measure labelled 6x is 30degrees

Step-by-step explanation:

Find the diagram attached

from the diagram;

6x = 30 (vertically opposite angle)

Divide both sides by 6

6x/6 = 30/6

x = 5

Get the angle labelled 6x

6x = 6(5)

6x = 30degrees

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3 years ago

Which angle is complementary to

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Answer:

angle GKF because it is complementary to angle JKG.

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Apply the distributive property and the greatest common factor to write an equivalent expression.

myrzilka [38]

You can take out a 12 from each factor as they can both be divided by 12. That leaves you with 12(5x-2) if you applied the distribution property, you'd end up with the same answer you started with.

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4 years ago

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Find the pattern and use it to list the next two terms in the sequence.

Sonbull [250]

Hello,

$u_{1} =3=3*1=3*1!*(-1)^{1-1}\\\\
 u_{2} =-6=3*(-2)=3*2!*(-1)^{2-1}\\
 u_{3} =18=3*3!*(-1)^{3-1}\\
 u_{4} =-72=3*4!*(-1)^{4-1}\\
 u_{5} =360=3*5!*(-1)^{5-1}\\
 u_{6} =-2160=3*6!*(-1)^{6-1}\\
 u_{7} =15120=3*7!*(-1)^{7-1}\\
 u_{8} =-120960=3*8!*(-1)^{8-1}\\\\

\boxed{ u_{n} =3*n!*(-1)^{n-1}}\\





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4 years ago

The lengths of two sides of a triangle are shown below:

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<u>Part A</u>

<u /> $3x^2 -2x-1+9x+2x^2 -3=\boxed{5x^2 + 7x-4}$

<u>Part B</u>

<u /> $(5x^3 +4x^2 - x-3)-(5x^2 + 7x-4)=\boxed{5x^3 - x^2 - 8x+1}$

<u>Part C</u>

No, because although they provide examples for specific polynomials being closed under addition and subtraction, there is a loss of generality.

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2 years ago