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Ipatiy [6.2K]
2 years ago
6

The lengths of two sides of a triangle are shown below:

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
6 0

<u>Part A</u>

<u />3x^2 -2x-1+9x+2x^2 -3=\boxed{5x^2 + 7x-4}

<u>Part B</u>

<u />(5x^3 +4x^2 - x-3)-(5x^2 + 7x-4)=\boxed{5x^3 - x^2 - 8x+1}

<u>Part C</u>

No, because although they provide examples for specific polynomials being closed under addition and subtraction, there is a loss of generality.

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The diameter of a circle is 6 in. Find its area to the nearest tenth.
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Answer and Step-by-step explanation:

The area formula for a Circle is:

A = \pi r^2

Diameter is equal to the radius times 2.

<u>So, divide the diameter to get the radius.</u>

6 divided by 2 equals 3.

<u>Now, plug it into the formula.</u>

A = \pi (3)^{2}

A = 9\pi

Plug this into your calculator by multiplying 9 by pi.

<u>We get the answer to be 28.3 when rounded to the nearest tenth.</u>

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If GJ = 7 and HJ = 6, then H _____ G. Choose the relationship symbol that would make a true statement. &lt; = &gt;
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an oil company conducts a geological study that indicates that an exploratory oil well should have a 20% chance of striking oil.
bazaltina [42]

Answer:

4.92% probability that the third strike comes on the seventh well drilled

Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a strike, or it is not. Each drill is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% chance of striking oil.

This means that p = 0.2

What is that probability that the third strike comes on the seventh well drilled

2 stikers during the first 6 drills(P(X = 2) when n = 6)[/tex]

Strike during the 7th drill, with 0.2 probability. So

P = 0.2P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{6,2}.(0.2)^{2}.(0.8)^{4} = 0.2458

Then

P = 0.2P(X = 2) = 0.2*0.2458 = 0.0492

4.92% probability that the third strike comes on the seventh well drilled

3 0
3 years ago
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