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2 years ago

The lengths of two sides of a triangle are shown below:

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

6 0

Part A

$3x^2 -2x-1+9x+2x^2 -3=\boxed{5x^2 + 7x-4}$

Part B

$(5x^3 +4x^2 - x-3)-(5x^2 + 7x-4)=\boxed{5x^3 - x^2 - 8x+1}$

Part C

No, because although they provide examples for specific polynomials being closed under addition and subtraction, there is a loss of generality.

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The diameter of a circle is 6 in. Find its area to the nearest tenth.

Marrrta [24]

Answer and Step-by-step explanation:

The area formula for a Circle is:

A = $\pi r^2$

Diameter is equal to the radius times 2.

So, divide the diameter to get the radius.

6 divided by 2 equals 3.

Now, plug it into the formula.

$A = \pi (3)^{2}$

A = $9\pi$

Plug this into your calculator by multiplying 9 by pi.

We get the answer to be 28.3 when rounded to the nearest tenth.

#teamtrees #PAW (Plant And Water)

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3 years ago

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3 years ago

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pantera1 [17]

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3 years ago

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Stephanie read 72 pages on Sunday and 83 pages on Monday . About how many pages did Stephanie read during the two days ?

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3 years ago

an oil company conducts a geological study that indicates that an exploratory oil well should have a 20% chance of striking oil.

bazaltina [42]

Answer:

4.92% probability that the third strike comes on the seventh well drilled

Step-by-step explanation:

For each drill, there are only two possible outcomes. Either it is a strike, or it is not. Each drill is independent of other drills. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% chance of striking oil.

This means that $p = 0.2$

What is that probability that the third strike comes on the seventh well drilled

2 stikers during the first 6 drills(P(X = 2) when n = 6)[/tex]

Strike during the 7th drill, with 0.2 probability. So

$P = 0.2P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.2)^{2}.(0.8)^{4} = 0.2458$

Then

$P = 0.2P(X = 2) = 0.2*0.2458 = 0.0492$

4.92% probability that the third strike comes on the seventh well drilled

3 0

3 years ago