Answer:
33.3% probability that both children are girls, if we know that the family has at least one daughter named Ann.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The family has two children.
The sample space, that is, the genders of the children may be divided in the following way, in which b means boy and g means girl.
b - b
b - g
g - b
g - g
We know that they have at least one girl. So the sample space is:
b - g
g - b
g - g
What is the probability that both children are girls, if we know that the family has at least one daughter named Ann?
Desired outcomes:
Both children being girls, so
g - g
1 desired outcome
Total outcomes
b - g
g - b
g - g
3 total outcomes
Probability
1/3 = 0.333
33.3% probability that both children are girls, if we know that the family has at least one daughter named Ann.
Answer:
R3 Theorem: If parallel lines are cut by a transversal, then alternate interior angles are congruent.
R4 Theorem: Congruence of segments is reflexive.
S5 ΔABC ≅ ΔCDA
Answer:
A. 4
Step-by-step explanation:
First, we can try the first option. 2/4 is equivalent to 6/12 when you multiply the fraction by 3 to get a common denominator. Since 6/12 is larger than 4/12, and the question has 1 answer, 4 is the only value that satisfices the statement and is the answer.
Answer:
It's rise/run.
May or not be right but I hope it helps!
I added the attachment.
I’m not sure if this is a question, but yes, i like to use “PEMDAS”.
Parentheses, exponents, multiply, divide, add, subtract.
You always go in order from left to right!