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Lemur [1.5K]
3 years ago
9

I need help please #19

Mathematics
1 answer:
o-na [289]3 years ago
5 0

Answer:

40

Step-by-step explanation:

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If a histogram is right skewed, which will be greater the mean or the median? Type a single word answer in the space
Mandarinka [93]

Answer:

Mean is greater

Step-by-step explanation:

For a skewed distribution, then the tail is longer to one side from the center than to the other. In a right skewed distribution, the tail is longer to the right.

When a distribution is skewed, the mean will be closer to the tail Than the median. Therefore. For a right skewed histogram, the mean is closer to the tail of the histogram and hence closer to the right. Once this happens, values closer to the right of a distribution are higher (number line). Thus the mean will be greater than the median.

8 0
3 years ago
Evaluate x^2 − 4x + 5, when x = − 3
Gnom [1K]

Answer:

\huge\boxed{26}

Step-by-step explanation:

\sf x^2-4x+5\\Given \ that \ x = -3\\(-3)^2-4(-3)+5\\9+12+5\\26

3 0
3 years ago
Read 2 more answers
Help in the question above please
Shkiper50 [21]

Answer:

A)11

Step-by-step explanation:

These are matrices one dimensional with one column and 3 rows each.

-The product of the matrices is obtained by multiplying the correspond values and summing up;

pq=\left[\begin{array}{ccc}3\\2\\-1\end{array}\right] \times\left[\begin{array}{ccc}5\\-1\\2\end{array}\right] \\\\\\\\=(3\times 5)+(2\times -1)+(-1\times 2)\\\\=15+-2+-2\\\\=11

Hence, the product of p and q is 11

4 0
3 years ago
3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are
natta225 [31]

Using the binomial distribution, the probabilities are given as follows:

a) 0.4159 = 41.59%.

b) 0.5610 = 56.10%.

c) 0.8549 = 85.49%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

n = 3, p = 0.76.

Item a:

The probability is P(X = 2), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159

Item b:

The probability is P(X < 3), hence:

P(X < 3) = 1 - P(X = 3)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390

Then:

P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.

Item c:

The probability is:

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
Rick bought some tetra fish and goldfish for his fish tank. He bought twice as many goldfish as he did tetras. Each goldfish cos
OlgaM077 [116]
1.50y(2)+2.00x=20

Now use the quadratic formula to solve 
6 0
3 years ago
Read 2 more answers
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